dy/dx= 9/(x+1)^2+9x(-2)/(x+1)^3=m
solve for m at x=0,
dy/dx= 9
y= mx+b
at (o,0), b=0
so
y=9x is the equation for the line.
check my work.
Find an equation of the tangent line to the curve at the given point.
y= (9x)/(x+1)^2 P = (0,0)
1 answer