Point-slope form of a linear equation is given by:
y - y₁ = m(x - x₁)
where (x₁, y₁) represents the given point and m represents the slope.
Plugging in the values m = 6/7 and (x₁, y₁) = (3, -1):
y - (-1) = (6/7)(x - 3)
Simplifying the equation:
y + 1 = (6/7)(x - 3)
Further simplifying:
y + 1 = (6/7)x - 18/7
Subtracting 1 from both sides:
y = (6/7)x - 18/7 - 1
Simplifying:
y = (6/7)x - 18/7 - 7/7
y = (6/7)x - 25/7
Therefore, the equation of the line with a slope of 6/7 and passing through the point (3, -1) is y = (6/7)x - 25/7.
Find an equation of the line having the given slope and containing the given point.
m = 6/7, (3, -1) Solve for y.
1 answer