The equation of a line can be written in the form y = mx + b, where m is the slope and b is the y-intercept.
Given that the slope m = 8/9 and the point (5, -9) lies on the line, we can substitute these values into the equation to find the y-intercept b.
-9 = (8/9)(5) + b
-9 = 40/9 + b
-9 - 40/9 = b
-81/9 - 40/9 = b
-121/9 = b
So the value of b is -121/9.
Therefore, the equation of the line with slope m = 8/9 and passing through the point (5, -9) is y = (8/9)x - 121/9.
Find an equation of the line having the given slope and containing the given point.
m = 8/9, (5, -9)
1 answer