The equation of a line can be written in the form y = mx + b, where m is the slope and b is the y-intercept.
Given that the slope (m) is four fifths and the point (6, -6) is on the line, we can substitute these values into the equation to find the value of b.
-6 = (4/5)(6) + b
Simplifying,
-6 = 24/5 + b
To find b, we need to isolate it on one side of the equation. We can do this by subtracting 24/5 from both sides.
-6 - 24/5 = b
To simplify this expression, we need to find a common denominator.
-30/5 - 24/5 = b
-54/5 = b
So, the value of b is -54/5.
Now that we have the values of m and b, we can substitute them back into the equation y = mx + b.
Therefore, the equation of the line is:
y = (4/5)x - 54/5
Find an equation of the line having the given slope and containing the given point.
m equals four fifths, (6,negative 6)
1 answer