To find an equation of the line, we can use the point-slope form, which is given by:
y - y₁ = m(x - x₁)
where m is the slope and (x₁, y₁) is the given point.
In this case, the slope is five sixths (5/6), and the given point is (9, -2).
Substituting these values into the point-slope form:
y - (-2) = (5/6)(x - 9)
Simplifying:
y + 2 = (5/6)(x - 9)
To solve for y, we need to isolate it on one side of the equation. We can start by distributing the (5/6) to the terms inside the parentheses:
y + 2 = (5/6)x - (5/6)(9)
Simplifying:
y + 2 = (5/6)x - 15/2
Next, we can move the constant term (2) to the other side of the equation by subtracting it from both sides:
y = (5/6)x - 15/2 - 2
Simplifying:
y = (5/6)x - 15/2 - 4/2
Combining like terms:
y = (5/6)x - 19/2
Therefore, the equation of the line with a slope of five sixths and containing the point (9, -2) is y = (5/6)x - 19/2.
Find an equation of the line having the given slope and containing the given point. Solve for y.
m = five sixths, (9, -2)
1 answer