Find an equation of the line having the given slope and containing the given point.

m = 5/6​, ​(9​, -2​)

1 answer

Using the point-slope form of a linear equation, we have:

y - y₁ = m(x - x₁)

where m is the slope and (x₁, y₁) is the given point.

Plugging in the values m = 5/6 and (x₁, y₁) = (9, -2), we get:

y - (-2) = (5/6)(x - 9)

Simplifying:

y + 2 = (5/6)(x - 9)

Multiplying both sides by 6:

6(y + 2) = 5(x - 9)

Expanding:

6y + 12 = 5x - 45

Subtracting 5x and 12 from both sides:

5x - 6y = 57

Therefore, the equation of the line with a slope of 5/6 and containing the point (9, -2) is 5x - 6y = 57.