The equation of the line with slope m and containing the point (x₁, y₁) is given by:
y - y₁ = m(x - x₁)
Substituting the slope m = -7 and the point (x₁, y₁) = (5, 8):
y - 8 = -7(x - 5)
Distributing -7 on the right side:
y - 8 = -7x + 35
Adding 8 to both sides:
y = -7x + 43
Therefore, the equation of the line with a slope of -7 and passes through the point (5, 8) is y = -7x + 43.
Find an equation of the line having the given slope and containing the given point.
m = -7, (5,8)
1 answer