Find an equation of parabola that has the indicated vertex and whose graph passes through the given point.
Vertex (-3,5)
Point (-6,1)
2 answers
****Point(-6,-1)
from the vertex, we know that
y = a(x+3)^2+5
Now plug in the values to get a:
1 = a(-6+3)^2 + 5
9a = -4
a = -4/9
y = -4/9 (x+3)^2 + 5
See
http://www.wolframalpha.com/input/?i=y+%3D+-4%2F9+%28x%2B3%29^2+%2B+5
y = a(x+3)^2+5
Now plug in the values to get a:
1 = a(-6+3)^2 + 5
9a = -4
a = -4/9
y = -4/9 (x+3)^2 + 5
See
http://www.wolframalpha.com/input/?i=y+%3D+-4%2F9+%28x%2B3%29^2+%2B+5
0 answers