2x+3y=2 has slope -2/3
So, using the point-slope form, the new line is
y-0 = -2/3 (x-0)
y = -2/3 x
y+4=0
y = -4 has slope 0
the horizontal line through (-5,3) is
y=3
Find an equation of a line parallel to the given line and contains the given point. Write the equation in slope-intercept form.
a. line 2x+3y=2 , point (0,0)
b. line y+4=0, Point (-5,3)
1 answer
1 answer