2a = 4
a = 2
e = c/a
c/2 = 3/2
c = 3
in a hyperbola:
a^2 + b^2 = c^2
4 + b^2 = 9
b^2 = 5
a^2 = 4
centre is (-2,3)
(x+2)^2 /4 - (y-3)^2 /5 = 1
Find an equation of a hyperbola with vertices (0,3) and (−4,3) and e=3/2.
Thank you
1 answer
1 answer