Given two points (x1,y1) and (x2,y2), the slope of the line passing through these points is given by:
slope = (y2-y1)/(x2-x1)
Using the coordinates (3,3) and (-3,-1):
slope = (-1-3)/(-3-3) = -4/6 = -2/3
Using the point-slope formula y-y1=m(x-x1), and substituting the point (3,3) and slope obtained, we get:
y-3 = (-2/3)(x-3)
Simplifying and expressing in slope-intercept form, we get the equation of line as:
y = (-2/3)x + 5
Find an equation for the line that passes through the points:
(x,y)=(3,3) and (x,y)=(-3,-1)
Express answer in slope-intercept form.
2 answers
WRONG ANSWER by the bot
two points: (3,3) and (-3,-1)
slope = (-1-3)/(-3-3) = -4/-6 = 2/3
using the point-slope method
y - 3 = (2/3)(x - 3)
3y - 9 = 2x - 6
2x - 3y = -3
or
-3y = -2x - 3
y = (2/3)x + 1
two points: (3,3) and (-3,-1)
slope = (-1-3)/(-3-3) = -4/-6 = 2/3
using the point-slope method
y - 3 = (2/3)(x - 3)
3y - 9 = 2x - 6
2x - 3y = -3
or
-3y = -2x - 3
y = (2/3)x + 1