find an equation for the hyperbola vertices (3,0),(3,4) asymptotes:y=2/3,y=4-2/3x

Answer 1

center midway between vertices at (3,2)
slope of asymptote 2/3 = a/b

(y-2)^2/4 - (x-3)^2/9 = 1

Answer 2

thank you very much