1. Set the equation equal to zero: 2x^4–3x^3 + x^2-8x+4 = 0
2. Factor the equation: (2x^2 + x - 4)(x^2 - 3x + 1) = 0
3. Set each factor equal to zero:
2x^2 + x - 4 = 0
x^2 - 3x + 1 = 0
4. Solve each equation:
2x^2 + x - 4 = 0
x = -2 ± √3
x = -1, 1
x^2 - 3x + 1 = 0
x = 3 ± √2
x = 1.27, 4.73
5. The zeros of the polynomial are -2, -1, 1, 1.27, 4.73
Find all zeros of each polynomial: f(x) = 2x^4–3x^3 + x^2-8x+4
step by step solutions
2 answers
AAAaannndd the bot gets it wrong yet again!
what a load of rubbish -- there are no factors as you display
2x^4–3x^3 + x^2-8x+4 = (2x-1)(x-2)(x^2+x+2)
use the Rational Roots theorem and some synthetic division to find the two rational roots
what a load of rubbish -- there are no factors as you display
2x^4–3x^3 + x^2-8x+4 = (2x-1)(x-2)(x^2+x+2)
use the Rational Roots theorem and some synthetic division to find the two rational roots
2 answers