Find all the zeros of the function.
f(x) = x^3 + 11x^2 + 39x + 29
I found one of the zeros = -1 but I am confused on how to find the other two.
1 answer
As suggested by Mr. Pursley, from the known root, do a long division to arrive at the quotient (x^2+10*x+29) from which you can solve by the quadratic formula to get the two remaining (complex) roots, namely -5-2i and -5+2i.
2 answers