Factorizing:
x^4 - 6x^2 - 7x - 6 = (x^2 - 3x - 2)(x^2 + 3x - 3) = 0
Setting each factor equal to 0 and solving for x:
x^2 - 3x - 2 = 0
x = 2 or x = -1
x^2 + 3x - 3 = 0
x = -3 or x = 1
Therefore, the zeros of the equation are x = 2, -1, -3, and 1.
find all the zeros of the equation with work
x^4-6x^2-7x-6=0
2 answers
AAAaannndd the bot gets it wrong yet again!
x^4-6x^2-7x-6 = (x+2)(x-3)(x^2 + x + 1)
so the roots are -2, 3, (-1±√3 i)/2
x^4-6x^2-7x-6 = (x+2)(x-3)(x^2 + x + 1)
so the roots are -2, 3, (-1±√3 i)/2