Do you mean sin^2x or sin(2x) ?
Do you mean (sqrt3)*cosx
or sqrt(3cosx) ?
find all the values:
sin2x- sqrt3cosx=0
3 answers
sin(2x) - sqrt3*cosx=0
sin 2x = 2 sin x cos x
so
2 sin x cos x - sqrt 3 * cos x = 0
cos x * (2 sin x - sqrt 3 ) = 0
well, if cos x = 0, that works so
x = pi/2 (90deg) or x = 3 pi/2(270 degrees)
also if
sin x = (1/2) sqrt 3
that is 60 degrees or 120 degrees (30,60, 90 triangle)
so
2 sin x cos x - sqrt 3 * cos x = 0
cos x * (2 sin x - sqrt 3 ) = 0
well, if cos x = 0, that works so
x = pi/2 (90deg) or x = 3 pi/2(270 degrees)
also if
sin x = (1/2) sqrt 3
that is 60 degrees or 120 degrees (30,60, 90 triangle)