Ask a New Question
Menu

Find all the solutions of the equation 2sin2xcos-2sinx=0 over the interval

-pi/2 <x≤ pi/2.

1 answer

2sin2x cos-2sinx=0
4sinx cosx - 2sinx = 0
2sinx(2cosx - 1) = 0
sinx=0, cosx = 1/2
Similar Questions
  1. Find all the solutions of the equation in the interval (0,2pip)sin(x + pi/6) - sin(x -pi/6) = 1/2 I am only stuck on the last
    1. answers icon 0 answers
  2. Find all the solutions of the equation in the interval (0,2pip)sin(x + pi/6) - sin(x -pi/6) = 1/2 I am only stuck on the last
    1. answers icon 4 answers
    1. answers icon 4 answers
    1. answers icon 1 answer
more similar questions