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Find all the solutions of the equation 2sin2xcos-2sinx=0 over the interval
-pi/2 <x≤ pi/2.
1 answer
2sin2x cos-2sinx=0
4sinx cosx - 2sinx = 0
2sinx(2cosx - 1) = 0
sinx=0, cosx = 1/2
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