really?
2tanx sinx + 2tanx = 0
2tanx (sinx + 1) = 0
tanx = 0
sinx = -1
You should be able to take it from there.
and when posting a question, don't bother with things like
Give the exact solution, including "pi" for π. For any unused answer boxes, enter DNE in all capital letters.
Instructions for input format are for you -- they have nothing to do with solving the problem.
Find all solutions to the given equation in the interval [0,2π). Give the exact solution, including "pi" for π. For any unused answer boxes, enter DNE in all capital letters.
2tanxsinx+2tanx=0
explanation please...thank you much
2 answers
sorry we are not as smart as you Oobleck
but thank you
but thank you