Find all solutions to the following system of equations:

x + 3y + 2z = 6
-3x + y + 5z = 29
-2x - 3y + z = 14

This just did not work out for me. Here is my work:

I first solved Equation #1 for x.

x = -3y - 2z + 6

Then, I did substitution, and replaced x for -3y - 2z + 6 in equations #2 and 3.

-3(-3y - 2z +6) + y + 5z = 29
-2(-3y - 2z +6) - 3y + z = 14

That is the same as:

10y + 11z = 47
and
3y + 5z = 26

Would elimination be the next step?

Thanks, Liese

2 answers

why not use elimination right from the beginning
look at the y's
If you add the first and the last, they are gone
If you add 3times the second to the last, they are gone.

now you have 2 equations in x and z

not bad....
I finished it up like I said with elimination and got y = -3. Is this correct?

If not, I'll try it the way you suggested with elimination the whole way through.

Thanks, Liese
Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
  1. Find the number of the solutions to each system.a. 4x-y+1=0 4x-y+3=0 b. 2x-y+4=0 4x-2y+8=0 Write a question that can be solved
    1. answers icon 2 answers
  2. The equationsx+ ky + 2z =0 x + (2k-1)y + 3z =0 x + ky + (k+3)z = 2k-1 Find the values of k such that a) the system has a unique
    1. answers icon 0 answers
more similar questions