sec x = -2, so
cos x = -1/2
solutions in QII and QIII
Find all solutions of the equation in the interval [0,2pi).
sec(theta)+2=0
Write your answer in radians in terms of pi
3 answers
how do I write this in radians in radians in terms of pi
c'mon, guy.
cos π/3 = 1/2, so
cos 2π/3 = cos 4π/3 = -1/2
x = 2π/3 or 4π/3
cos π/3 = 1/2, so
cos 2π/3 = cos 4π/3 = -1/2
x = 2π/3 or 4π/3