To find the solutions of the equation, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac))/(2a)
In this case, a = 1, b = 12, and c = 37. Plugging these values into the quadratic formula, we have:
x = (-12 ± √(12^2 - 4(1)(37)))/(2(1))
x = (-12 ± √(144 - 148))/(2)
x = (-12 ± √(-4))/(2)
x = (-12 ± 2i)/(2)
x = -6 ± i
So, the solutions to the equation x^2 + 12x + 37 = 0 can be expressed as -6 + i and -6 - i.
Find all solutions of the equation and express them in the form a+bi
X^2+12x+37=0
1 answer