(2sinx +1)(sinx +1) = 0
2sinx + 1 = 0 sinx + 1 = 0
sinx = -1/2 sinx = -1
Can you find x? There are two possible values for the first part and one possible value for the second part given the interval.
Find all solutions of the equation 2sin^2 x + 3sinx+1 = 0
over the interval [0,2pi)
1 answer