Find all solutions of the equation 2sin^2 x + 3sinx+1 = 0

over the interval [0,2pi)

1 answer

(2sinx +1)(sinx +1) = 0

2sinx + 1 = 0 sinx + 1 = 0
sinx = -1/2 sinx = -1

Can you find x? There are two possible values for the first part and one possible value for the second part given the interval.