cos^2x-5sinx+5=0
1-sin^2x - 5sinx + 5 = 0
sin^2x + 5sinx - 6 = 0
(sinx+6)(sinx-1) = 0
so,
sinx = -1/6 or 1
Now you can find x. Watch for signs in quadrants.
Find all solutions (if they exist)for the given equation on the interval [0,2pi)
cos^2x-5sinx+5=0
1 answer
2 answers