theta = arctan2 or arctan -2
because tan^2 = 4, so tan is +/- 2
that's as exact as you can get. Just as pi or sqrt(7) is a perfectly valid number, so is arctan(2)
just be sure to note that since arctan(-2) = pi-arctan(2), the complete solution set is
k*pi+/-Arctan(2)
where Arctan(2) is the principal value.
find all solutions for
tan^2 theta -4 = 0
i got theta = arctan 2
is that correct? and if it is how would i write it as a solution?
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