Find all solutions (answers should be given in simplified form). Some answers may involve the number i.

*I will use lowercase l to represent absolute value lines.*

3 lx-1l + 4 = 19

We've never really worked with absolute value in solving equations before. Do I distribute the 3 to the x-1 as normal, or do something different?

This is my first idea:

3 lx-1l = 15

lx-1l = 5

x = -4, 6

1 answer

No, you do not distribute the absolute value signs.
What you did is correct, i.e. keep the absolute value quantity intact, and eventually evaluate the value as either positive or negative.
|x-1|=5 means
x-1=5 => x=5+1=6
or
-(x-1)=5 => x=1-5=-4
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