Find all sets of three consecutive multiples of 11 for which the sum of two lesser numbers is greater than 100 and the sum of the two greater numbers is less than 200

Answer 1

11x + 11(x+1) > 100
11(x+1) + 11(x+2) < 200

22x > 89
22x < 167

4.04 < x < 7.59

So, the numbers can be

55 66 77
66 77 88
77 88 99