Let y=x²
the equation can then be written as
4y²+15y-4=0
Solve for y using the quadratic formula (i.e. find y1 and y2).
Since y=x², then
x=±√(y1) or ±√(y2)
giving a total of 4 solutions.
Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.)
4x4 + 15x2 − 4 = 0
2 answers
Find all real solutions of the equation by first rewriting the equation as a quadratic equation. (Enter your answers as a comma-separated list.)
4^4 + 15^2 − 4 = 0
4^4 + 15^2 − 4 = 0
1 answer