let x^(1/3) = y, then your equation becomes
y^2 - 2 = y
y^2 - y - 2 = 0
(y-2)(y+1) = 0
y = 2 or y = -1
then
x^(1/3) = 2
x = 8
or
x^(1/3) = -1
x = -1
find all real and imaginary solutions
x^(2/3)-2=x^(1/3)
1 answer