all points (x,y) that are 13 units away from the point (2,7) defines a circle:
(x-2)^2 + (y-7)^2 = 169
so, the line x-2y=10 may intersect the circle in 0,1, or 2 points.
So, plug x=2y+10 into the equation of the circle and see where the two graphs intersect.
Find all points (x,y) that are 13 units away from the point (2,7) and that lie on the line x - 2y = 10. Give your answer as a list of points separated by semicolons, with the points ordered such that their x-coordinates are in increasing order. So "(1,-3); (2,3); (5,-7)" - without the quotes - is a valid answer format.)
2 answers
see whether you get what wolframalpha does:
https://www.wolframalpha.com/input/?i=solve+%28x-2%29^2+%2B+%28y-7%29^2+%3D+169,+x-2y%3D10
https://www.wolframalpha.com/input/?i=solve+%28x-2%29^2+%2B+%28y-7%29^2+%3D+169,+x-2y%3D10