To find the values that must be excluded from the domain of the rational expression \(\frac{x-2}{x^2 + 9x + 8}\), we need to identify when the denominator is zero.
First, we will set the denominator equal to zero and solve for \(x\):
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Set the denominator equal to zero: \[ x^2 + 9x + 8 = 0 \]
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Factor the quadratic expression: \[ x^2 + 9x + 8 = (x + 1)(x + 8) \]
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Set each factor to zero: \[ x + 1 = 0 \quad \Rightarrow \quad x = -1 \] \[ x + 8 = 0 \quad \Rightarrow \quad x = -8 \]
Thus, the values that must be excluded from the domain are \(x = -1\) and \(x = -8\).
So, the answer is: \[ -1, -8 \]
This means that the rational expression \(\frac{x-2}{x^2 + 9x + 8}\) is undefined for \(x = -1\) and \(x = -8\).