Asked by math
find all nonnegative integer solutions of the system
x+y<8
x+t<8
t+y<8
z+t<8
x+y<8
x+t<8
t+y<8
z+t<8
Answers
Answered by
Steve
if t=0, we have
x<8
y<8
z<8
x+y<8
so, 0<x<8, y<8-x, z<8
List them all.
If t=1, change the 8's to 7's in the first 3 conditions.
And so on, up to t=7:
x<1
y<1
z<1
x+y<8
(x,y,z,t) = (0,0,0,7)
Don't see the point of the exercise, but there it is.
x<8
y<8
z<8
x+y<8
so, 0<x<8, y<8-x, z<8
List them all.
If t=1, change the 8's to 7's in the first 3 conditions.
And so on, up to t=7:
x<1
y<1
z<1
x+y<8
(x,y,z,t) = (0,0,0,7)
Don't see the point of the exercise, but there it is.
Answered by
math
sory a mistake, the corect one problem is find all nonnegative integer solutions of the system
x+y<8
x+Z<8
t+y<8
z+t<8
x+y<8
x+Z<8
t+y<8
z+t<8
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