find all discontinuities (16x/2x3-8x3=0)

1 answer

You are probably not getting a reply because this is a confusing question.

you write it as an equation, equations have solutions, we don't speak of discontinuities for equations

Secondly, is the denominator 2x^3 - 8x^3
or only 2x^3 , the way you typed it.

Thirdly, if the denominator is 2x^3 - 8x^3, why was it not simplified to -6x^3

Is there a typo??
Similar Questions
  1. f(x) = (x - 2) / (x^2 - 3x + 2)For the function above, find and the discontinuities and identify what types of discontinuities
    1. answers icon 3 answers
    1. answers icon 1 answer
  2. Find the discontinuities (if any) of each function1. f(x) = 1/(x-4) If there is point(s) of discontinuities then x = , x = 2.
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions