Question

Find all critical numbers:

2x*sqrt(3x^2+4)?

Answer 1

is this
y = 2x*sqrt(3x^2+4) ?

critical number are
x and y intercepts, max/min points and points of inflection

for x-intercept, let y = 0
for y-intercept , let x = 0

for max/min , take first derivative, set equal to zero and solve for x. Sub back into original to get the matching y

for pts. of inflection, set second derivative to zero and solve for x
sub back into original to get the y

use product rule to find first derivative.