Find a unit vector in the direction of the given vector.

Question

v=(1,-1)

Answer 1

for any unit vector in the direction of (a,b)
....

find the length of the vector
= √(a^2+b^2)

now divide each component by that magnitude

to get (a/√(a^2+b^2) , b/√(a^2+b^2)
or you could write it as
(1/√(a^2+b^2) (a,b)

apply this to your vector, let me know what you got

apply this to your vector

Answer 2

I got (1/Square root of 2,-1/square root of 2)

Thanks

Answer 3

correct

notice you can check that the magnitude is 1

magnitude
= √( (1/√2)^2 + (-1/√2)^2 )
=√( 1/2 + 1/2)
= √1
= 1