Find a third-degree polynomial equation with rational coefficients that has roots –4 and 6 + i.

Question

(1 point)
Responses

x3 – 8x2 – 11x + 148 = 0
x 3 – 8 x 2 – 11 x + 148 = 0

x3 – 8x2 – 12x + 37 = 0
x 3 – 8 x 2 – 12 x + 37 = 0

x3 – 12x2 + 37x = 0
x 3 – 12 x 2 + 37 x = 0

x3 – 8x2 – 11x = 0

Answer 1

The correct equation is:

x^3 – 8x^2 – 11x + 148 = 0