Find a special factoring pattern for a difference of two sextics: (a^6-b^6).

Answer 1

first step:
(a^3 - b^3)(a^3 + b^3)

second step: we can factor the sum and difference of cubes, should be in your notes or text

= (a-b)(a^2 + ab + b^2)(a+b)(a^2 - ab + b^2)