since the zeros of the quadratic are -4 and 3
we can say:
f(x) = a(x+4)(x-3)
so the only thing we don't know is a possible coefficient.
but f(1) = - 30
-30 = a(1+4)(1-3)
-30 = -10a
a = 3
f(x) = 3(x+4)(x-3)
expand if so needed
Find a Quadratic polynomial function with real coefficients satisfying the given conditions.
-4 and 3 are zeros; f(1) = -30
HELP. I have no idea.
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