find a projectile fired with an initial velocity of 128 feet per second at an angle of 26 degrees

Answer 1

I assume I will find it where it landed. That would be where the height is zero.

y = tanθ x - g/(2(vcosθ)^2) x^2

In this case, that's

y = 0.4877x - 0.0012088x^2
y=0 at x=403.5

So, I'd start looking at 403.5 feet from where it was shot.

Did you have something else in mind when you said to find it?