No, take a look at the definition of the Maclaurin series. It starts with f(0). very power series starts with the first term of its defined sequence.
f = x/(1+2x)
f' = 1/(1+2x)^2
f(2) = -4/(1+2x)^3
f(3) = 24/(1+2x)^4
f(4) = -192/(1+2x)^5
from then on it's just the power rule:
f(n) = (-2)^(n-1) n! (1+2x)^-(n+1)
so, we have
f(0) + 1/1! f(1)(0) + 1/2! f(2)(0) + ...
= 0 + 1x - 4/2!x^2 + 24/3!x^3 - 192/4!x^4 + ...
= 0 + x - 2x^2 + 4x^3 - 8x^4 + ...
Find a power series, centered @ x=0, for function f(x)=x/(1+2x).
I know this is a maclaurin series, but my work doesn't get the right answer. Can you please show steps? Also,do all power series start with a 1, as in (1+2x+4x^2+...)?
Thanks in advance!
1 answer