Find a polynomial equation that has zeros at x = - 2 x = O x = 3 and x = 5

y = x(x + 2)(x - 3)(x - 5)

y = (x + 2)(x - 3)(x - 5)

y = (x - 2)(x - 3)(x - 5)

y = (x - 2)(x + 3)(x + 5)

1 answer

To find a polynomial that has zeros at \( x = -2 \), \( x = 0 \), \( x = 3 \), and \( x = 5 \), we can write it in factored form based on its zeros:

The factors corresponding to the given zeros are:

  • \( (x + 2) \) for the zero at \( x = -2 \)
  • \( (x - 0) \) or simply \( x \) for the zero at \( x = 0 \)
  • \( (x - 3) \) for the zero at \( x = 3 \)
  • \( (x - 5) \) for the zero at \( x = 5 \)

Therefore, the polynomial can be written as:

\[ y = (x + 2)(x)(x - 3)(x - 5) \]

Now, let's analyze the answer choices provided:

  1. \( y = x(x + 2)(x - 3)(x - 5) \) - This includes all zeros, which includes the correct factors.
  2. \( y = (x + 2)(x - 3)(x - 5) \) - This does not include the zero at \( x = 0 \).
  3. \( y = (x - 2)(x - 3)(x - 5) \) - This does not have any of the correct zeros specified.
  4. \( y = (x - 2)(x + 3)(x + 5) \) - This also does not match any of the specified zeros.

Among the choices, the only polynomial that correctly represents the given zeros is:

\[ \boxed{y = x(x + 2)(x - 3)(x - 5)} \]