The point-slope equation of a line is given by the formula:
y - y1 = m(x - x1)
where m is the slope and (x1, y1) is a point on the line.
In this case, the slope is 4/5 and the point on the line is (4, 6).
Substituting these values into the formula, we get:
y - 6 = (4/5)(x - 4)
Simplifying this equation, we multiply the slope 4/5 by (x - 4):
y - 6 = 4/5 * x - 4 * 4/5
y - 6 = 4/5 * x - 16/5
Combining like terms, we get:
y = 4/5 * x - 16/5 + 6
y = 4/5 * x - 16/5 + 30/5
y = 4/5 * x + 14/5
So, the point-slope equation of the line with a slope of 4/5 and passing through the point (4, 6) is y = 4/5 * x + 14/5.
Find a point-slope equation of the line having the given slope and containing the given point.
m = 4/5, (4,6)
1 answer