Let x be the number.
"the sum of itself and its cube is the same as twice the square if it"
x+x^3 = 2x^2.
Solve by factoring
x^3-2x^2+x=0
x(x^2-2x+1)=0
x(x-1)^2=0
x = 0,1
find a number where the sum of itself and its cube is the same as twice the square if it
1 answer