Find a formula for the exponential function that satisfies h(2)=22 and h(4)=14.08

Answer 1

if h(x) = ae^bx,
just plug in your values:
22 = ae^2b
14.08 = ae^4b

divide one by the other, and the a's cancel

14.08/22 = .64 = e^2b
e^b = .8

22 = a*.64
a = 34.375

h(x) = 34.375 e^bx = 34.375 * 0.8^x