Asked by Michael
                Find a formula  for an experienced equation that goes through the points 
(x,y)=(-2,50) and (x,y)=(0,2)
y=
            
        (x,y)=(-2,50) and (x,y)=(0,2)
y=
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                    Answered by
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    To find the formula for the equation that goes through the points (-2,50) and (0,2), we can use the slope-intercept form of a linear equation, which is:
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, we need to find the slope of the line. We can use the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (-2, 50) and (x2, y2) = (0, 2).
m = (2 - 50) / (0 - (-2))
m = -48 / 2
m = -24
Now we can substitute the slope and one of the points into the slope-intercept form to find the y-intercept:
y = mx + b
2 = (-24)(0) + b
b = 2
So the formula for the equation that goes through the points (-2,50) and (0,2) is:
y = -24x + 2
    
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, we need to find the slope of the line. We can use the formula:
m = (y2 - y1) / (x2 - x1)
where (x1, y1) = (-2, 50) and (x2, y2) = (0, 2).
m = (2 - 50) / (0 - (-2))
m = -48 / 2
m = -24
Now we can substitute the slope and one of the points into the slope-intercept form to find the y-intercept:
y = mx + b
2 = (-24)(0) + b
b = 2
So the formula for the equation that goes through the points (-2,50) and (0,2) is:
y = -24x + 2
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