r = 5cscØ
r = 5/sinØ
we know that y/r = sinØ
or r = y/sinØ
then y/sinØ = 5/sinØ
y = 5 , a horizontal line
check:
http://www.wolframalpha.com/input/?i=polar+plot+r%3D5cscx
Find a Cartesian equation for the curve and identify it.
r=5cscx
2 answers
r = 5 cscθ
r sinθ = 5
y = 5
r sinθ = 5
y = 5