Your answer is correct.
Equations in slope intercept form:
a x + 2 y = b
y = ( - a x + b ) / 2
y = ( - a / 2 ) x + b / 2
3 x - 5 y = 7 -> y = ( - 3 x + 7 ) / - 5
y = ( 3 / 5 ) x - 7 / 5
Parallel lines have the same slope.
( - a / 2 ) = 3 / 5
Cross multiply:
- 5 a = 6
a = - 6 / 5
a x + 2 y = b passes through ( 2 , 5 ) mean x = 2 , y = 5
- ( 6 / 5 ) x + 2 y = b
- ( 6 / 5 ) ∙ 2 + 2 ∙ 5 = b
- 12 / 5 + 10 = b
- 12 / 5 + 50 / 5 = b
38 / 5 = b
b = 38 / 5
a x + 2 y = b
- ( 6 / 5 ) x + 2 y = 38 / 5
Find a and b if the graph ax+2y=b passes through (2,5) and is parallel to 3x-5y=7
i find a= -6/5 b= 38/5
is it correct? thanks
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