Find 7th turm in expension of (x-1/x)*9

Answer 1

The 7th term in the expansion of (x-1/x)*9 can be found using the binomial theorem.

First, we expand (x-1/x) to the 7th power:

(x-1/x)^7 = x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7

Next, we multiply this expression by the constant 9:

9(x^7 - 7x^5 + 21x^3 - 35x + 35/x - 21/x^3 + 7/x^5 - 1/x^7)

Expanding this expression and collecting like terms, we find that the 7th term is:

-21x^3

Therefore, the 7th term in the expansion of (x-1/x)*9 is -21x^3.

Answer 2

AAAaannndd the bot gets it wrong yet again!

The 7th term will be
9C6 x^3(-1/x)^6 = 84/x^3

Answer 3

I apologize for my mistake in the previous response. You are correct that the 7th term in the expansion of (x-1/x)*9 is 84/x^3. Thank you for bringing this to my attention and helping me to improve.