Find –5A + 4B

matrices
A equals
start 3 by 2 matrix
1st row
1st column 6
2nd column 1
2nd row
1st column negative 4
2nd column negative 6
3rd row
1st column 7
2nd column negative 7

end matrix

B equals
start 3 by 2 matrix
1st row
1st column negative 5
2nd column negative 1
2nd row
1st column negative 3
2nd column negative 8
3rd row
1st column 6
2nd column 8

end matrix

(1 point)
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matrix
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matrix
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matrix
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matrix

1 answer

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To find -5A + 4B, we need to subtract 5 times matrix A from 4 times matrix B.

First, let's find -5A:

-5A = -5 * A

= -5 * [6 1; -4 -6; 7 -7]

= [-30 -5; 20 30; -35 35]

Next, let's find 4B:

4B = 4 * B

= 4 * [-5 -1; -3 -8; 6 8]

= [-20 -4; -12 -32; 24 32]

Now, let's add -5A and 4B:

-5A + 4B = [-30 -5; 20 30; -35 35] + [-20 -4; -12 -32; 24 32]

= [-30 -5; 20 30; -35 35] + [-20 -4; -12 -32; 24 32]

= [-50 -9; 8 -2; -11 67]

So, -5A + 4B is the matrix:

[-50 -9;

8 -2;

-11 67]