Ask a New Question
Menu

Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)

1 answer

(4x^2y^3 + 2xy^2 - 2y) - (-7x^2y^3 + 6xy^2 - 2y)
= 4x^2y^3 + 2xy^2 - 2y + 7x^2y^3 - 6xy^2 + 2y
= (4x^2y^3 + 7x^2y^3) + (2xy^2 - 6xy^2) + (-2y + 2y)
= 11x^2y^3 - 4xy^2
Similar Questions
  1. Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)Place the correct coefficients in the difference. _x^2y^3 + _xy^2 + _y
    1. answers icon 1 answer
  2. Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)Place the correct coefficients in the difference. x2y3 + _xy2 + _y
    1. answers icon 1 answer
    1. answers icon 2 answers
  4.  Simplify.(6x3y)(2xy2)(6x3y)(2xy2) Hint: Multiply the 6 and 2...then use the exponent rules for the variables.
    1. answers icon 1 answer
more similar questions