let the 4 consecutive even integers be
x, x+2, x+4, and x+6
so 2x + x+6 = 96
3x = 90
x = 30
So the 4 integers are 30,32,34, and 36
check : is twice the smallest plus the largest equal to 98
2(30) + 36 = 96
YeS!
You could have known your numbers are not correct by testing them.
Find 4 consecutive even integers such that twice the least increased by the greatest is 96........I got 10,12,14and 16 but not sure...please help!
2 answers
If I understand the question, 10, 12, 14 and 16 is not right.
Is 2 * 10 + 16 = 96?
Call the numbers a, b, c, d. We're really only interested in a and d.
How much bigger is d than a?
d = a + ?
Call the unknown x. d = a + x
Now, we know that 2a + d = 96
but we also know that d = a + x
So 2a + a + x = 96
3a = 96 - x
Is 2 * 10 + 16 = 96?
Call the numbers a, b, c, d. We're really only interested in a and d.
How much bigger is d than a?
d = a + ?
Call the unknown x. d = a + x
Now, we know that 2a + d = 96
but we also know that d = a + x
So 2a + a + x = 96
3a = 96 - x