Find 4 consecutive even integers such that twice the least increased by the greatest is 96........I got 10,12,14and 16 but not sure...please help!

Answer 1

let the 4 consecutive even integers be
x, x+2, x+4, and x+6

so 2x + x+6 = 96
3x = 90
x = 30

So the 4 integers are 30,32,34, and 36

check : is twice the smallest plus the largest equal to 98
2(30) + 36 = 96
YeS!

You could have known your numbers are not correct by testing them.

Answer 2

If I understand the question, 10, 12, 14 and 16 is not right.

Is 2 * 10 + 16 = 96?

Call the numbers a, b, c, d. We're really only interested in a and d.

How much bigger is d than a?

d = a + ?

Call the unknown x. d = a + x

Now, we know that 2a + d = 96

but we also know that d = a + x

So 2a + a + x = 96

3a = 96 - x